document.write( "Question 74745: 5c=3c +10 What is the equation? \n" ); document.write( "

Algebra.Com's Answer #53720 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
If you're trying to solve for c, then:
\n" ); document.write( " $\"5c-3c=cross%283c-3c%29+%2B10\"$ Subtract 3c from both sides
\n" ); document.write( " $\"cross%282%2F2%29c=10%2F2\"$ Divide both sides by 2
\n" ); document.write( " $\"c=5\"$
\n" ); document.write( "

\n" ); document.write( "Check:
\n" ); document.write( " $\"5%285%29=3%285%29+%2B10\"$ plug in c=5
\n" ); document.write( " $\"25=15%2B10\"$
\n" ); document.write( " $\"25=25\"$ works
\n" ); document.write( " \n" ); document.write( "

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