document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888217>Question 888217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope of the line satisfying the given conditions: through (-9,-6) and (-5,8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537192 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two generic points that define a straight line are (x1, y1) and (x2, y2)\r<BR>\n" );
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document.write( "In this case, (x1, y1) = (-9, -6), which means x1=-9 and y1=-6\r<BR>\n" );
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document.write( "and (x2, y2) = (-5, 8), which means x2=-5 and y2=8\r<BR>\n" );
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document.write( "So x1=-9, y1=-6, x2=-5, and y2=8.\r<BR>\n" );
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document.write( "Now use the slope formula\r<BR>\n" );
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document.write( "m = (y2-y1)/(x2-x1)\r<BR>\n" );
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document.write( "m = (8-(-6))/(-5-(-9))\r<BR>\n" );
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document.write( "m = (8+6)/(-5+9)\r<BR>\n" );
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document.write( "m = 14/4\r<BR>\n" );
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document.write( "m = 7/2\r<BR>\n" );
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document.write( "So the slope of the line that passes through the two points is  7/2<BR>\n" );
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