document.write( "Question 888100: How many zeroes does \"y+=+12%2Fcos+%284x%29+%2B+4\" have, between 0 and 2pi ?
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Algebra.Com's Answer #537163 by Edwin McCravy(20081)\"\" \"About 
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document.write( "It does not have any zeros,\r\n" );
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document.write( "Since cos(4x)is always between -1 and +1, the first term has smallest\r\n" );
document.write( "positive velue when cos(4x) = 1 which gives \"y=12%2F1%2B4=16\", so 16\r\n" );
document.write( "is the minimum positive value.  The first term has largest negative value \r\n" );
document.write( "when cos(4x) = 1 which gives \"y=12%2F%28-1%291%2B4=-8\", so -8 is the maximum \r\n" );
document.write( "negative value.  The graph never crosses the x-axis and thus there are\r\n" );
document.write( "no zeros at all.\r\n" );
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document.write( "Edwin

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