document.write( "Question 888134:  Twelve men take 6 hours to finish a piece of work. After the 12 men have worked for 1 hour, the contractor decides\r
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document.write( "to call in 8 more men. How many more hours would 20 men take to complete the remaining work \n" );
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| Algebra.Com's Answer #537102 by josmiceli(19441)     You can put this solution on YOUR website! Twelve men take 6 hours to finish a piece of work. \n" ); document.write( "In 1 hour, the 12 men will finish 1/6 of the work \n" ); document.write( "( 1 job ) / ( 6 hrs ) = ( 1/6 of a job ) / ( 1 hr ) \n" ); document.write( "----------------------------------------- \n" ); document.write( "That means there is \n" ); document.write( "left to do. \n" ); document.write( "------------------- \n" ); document.write( "If 12 men take 6 hours to finish a piece of work, \n" ); document.write( "1 man will take 12 times as long, to finish the work, so \n" ); document.write( "( 1 job ) / ( 6*12 = 72 hrs ) = rate of working for 1 man, or \n" ); document.write( " \n" ); document.write( "------------------- \n" ); document.write( "After 1 hour, there are a total of \n" ); document.write( "20 men will work 20 times as fast as 1 man on the \n" ); document.write( "of a job that remains, so \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "---------- \n" ); document.write( "It will takes the 20 men 3 more hours to \n" ); document.write( "complete the remaining work \n" ); document.write( "-------------------------- \n" ); document.write( "Hope I got it\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |