document.write( "Question 888096: To find zeros of the fn. -
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Algebra.Com's Answer #537068 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Set the expression equal to zero. Factor and solve.\r
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\n" ); document.write( "\n" ); document.write( "x^4 - x^3 - 4x^2 + 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x^4 - x^3) + (-4x^2 + 4) = 0\r
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\n" ); document.write( "\n" ); document.write( "x^3(x - 1) + (-4x^2 + 4) = 0\r
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\n" ); document.write( "\n" ); document.write( "x^3(x - 1) -4(x^2 - 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "x^3(x - 1) -4(x - 1)(x + 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "x^3(x - 1) -4(x + 1)(x - 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "(x^3 - 4(x+1))(x - 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "Then you use the zero product property to get these two equations\r
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\n" ); document.write( "\n" ); document.write( "x^3 - 4(x+1) = 0 or x-1=0\r
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\n" ); document.write( "\n" ); document.write( "The first equation x^3 - 4(x+1) = 0 needs a calculator because this is a cubic (most cubics are nearly impossible to solve by hand)\r
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\n" ); document.write( "\n" ); document.write( "The approximate solution to x^3 - 4(x+1)=0 is x = 2.382975768\r
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\n" ); document.write( "\n" ); document.write( "The solution to x-1 = 0 is x = 1\r
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\n" ); document.write( "\n" ); document.write( "So the two real number solutions are\r
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\n" ); document.write( "\n" ); document.write( "x = 1 or x = 2.382975768
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