document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888015>Question 888015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+cot%28+sin%5E-1%28-1%2F2%29+-+sec%5E-1%282%29+%29+ ALIGN=MIDDLE  ALT=\"+cot%28+sin%5E-1%28-1%2F2%29+-+sec%5E-1%282%29+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >?\r<BR>\n" );
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document.write( "I have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x+=+sin%5E-1%28-1%2F2%29 ALIGN=MIDDLE  ALT=\"+x+=+sin%5E-1%28-1%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > implies sin x= -1/2 <BR>\n" );
document.write( "and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+y+=+sec%5E-1%282%29 ALIGN=MIDDLE  ALT=\"+y+=+sec%5E-1%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > implies sec y= 2. \r<BR>\n" );
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document.write( "But I'm not sure if cot( x - y) is the right way to go.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537011 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cot( sin^-1(-1/2) - sec^-1(2) )<BR>\n" );
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document.write( "If sin(x) = -1/2, x = 210 degrees<BR>\n" );
document.write( "If sec(y) = 2, y = 60 degrees<BR>\n" );
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document.write( "cot(210-60) = cot(50) = 0.8391<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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