document.write( "Question 887917: The half-life of carbon 14 is 5730 years. How old is a bone containing 20% of its original carbon 14? \n" ); document.write( "

Algebra.Com's Answer #537008 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"0.20X=X%281%2F2%29%5E%28T%2F5730%29\"$
\n" ); document.write( " $\"0.20=%281%2F2%29%5E%28T%2F5730%29\"$
\n" ); document.write( " $\"log%281%2F2%2C%280.2%29%29=T%2F5730\"$
\n" ); document.write( " $\"T%2F5730=%28log%28%280.2%29%29%2Flog%28%280.5%29%29%29\"$
\n" ); document.write( " $\"T=5730%2A%28log%28%280.2%29%29%2Flog%28%280.5%29%29%29\"$
\n" ); document.write( " $\"T=5730%2A2.322\"$
\n" ); document.write( " $\"T=13305\"$ $\"years\"$ \n" ); document.write( "

\n" );