document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74730>Question 74730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each of the following problems. Be sure to show the equations used for the solution.<BR>\n" );
document.write( "Business and finance. A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53695 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of $9.00 beans <BR>\n" );
document.write( "Then 100-x=amount of $12.00 beans\r<BR>\n" );
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document.write( "Now we know that the value of the $9.00 beans ($9.00)(x) plus the value of the $12.00 beans ($12.00)(100-x) must equal the value of the final mixture (100)($11.25).  So our equation to solve is:\r<BR>\n" );
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document.write( "$9.00x+$12.00(100-x)=(100)($11.25)  get rid of parens\r<BR>\n" );
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document.write( "$9.00x+$1200-$12.00x=$1125  subtract $1200 from both sides\r<BR>\n" );
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document.write( "$9.00x+$1200-$1200-$12.00x=$1125-$1200  collect like terms\r<BR>\n" );
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document.write( "-$3.00x=-$75  divide both sides by -$3.00\r<BR>\n" );
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document.write( "x=25 lb of $9.00 beans\r<BR>\n" );
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document.write( "100-x=100-25=75 lb of $12.00 beans\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "25*$9.00+75*$12.00=100($11.25)<BR>\n" );
document.write( "225+900=1125<BR>\n" );
document.write( "1125=1125\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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