document.write( "Question 887677: two years ago, a woman was seven times as old as her daughter but in three years she would be only four times as old as her daughter. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #536867 by josgarithmetic(39617)\"\" \"About 
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w for woman's age
\n" ); document.write( "d for daughter's age\r
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\n" ); document.write( "\n" ); document.write( "Two Years Ago: \"w-2=7%28d-2%29\"
\n" ); document.write( "\"w-2=7d-14\"
\n" ); document.write( "\"w-7d=2-14\"
\n" ); document.write( "\"w-7d=-12\"
\n" ); document.write( "\"highlight%287d-w=12%29\"\r
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\n" ); document.write( "\n" ); document.write( "In Three Years: \"w%2B3=4%28d%2B3%29\"
\n" ); document.write( "\"w%2B3=4d%2B12\"
\n" ); document.write( "\"w=4d%2B9\"
\n" ); document.write( "\"highlight%28w-4d=9%29\"\r
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\n" ); document.write( "\n" ); document.write( "Two equations in d and w. Solve both for w and equate the expressions, and solve for the value
\n" ); document.write( "of d. Find w from the now found d.
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