document.write( "Question 887677: two years ago, a woman was seven times as old as her daughter but in three years she would be only four times as old as her daughter. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #536867 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! w for woman's age \n" ); document.write( "d for daughter's age\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two Years Ago: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In Three Years: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two equations in d and w. Solve both for w and equate the expressions, and solve for the value \n" ); document.write( "of d. Find w from the now found d. \n" ); document.write( " \n" ); document.write( " |