document.write( "Question 887644: Jill paid $36 for calendars marked down $5 apiece from the original price. If she had bought them at the original price, she could have gotten 5 few calendars. How many calendars did she buy? \n" ); document.write( "
Algebra.Com's Answer #536829 by ankor@dixie-net.com(22740)\"\" \"About 
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Jill paid $36 for calendars marked down $5 apiece from the original price.
\n" ); document.write( " If she had bought them at the original price, she could have gotten 5 fewer calendars.
\n" ); document.write( " How many calendars did she buy?
\n" ); document.write( ":
\n" ); document.write( "let x = the number of calenders she bought
\n" ); document.write( "let p = the original price
\n" ); document.write( ":
\n" ); document.write( "\"Jill paid $36 for calendars marked down $5 apiece from the original price.\"
\n" ); document.write( "x(p - 5) = 36
\n" ); document.write( "px - 5x = 36
\n" ); document.write( ":
\n" ); document.write( "\" If she had bought them at the original price, she could have gotten 5 fewer calendars.\"
\n" ); document.write( "p(x - 5) = 36
\n" ); document.write( "px - 5p = 36
\n" ); document.write( "then we can:
\n" ); document.write( "px - 5x = 36
\n" ); document.write( "px - 5p = 36
\n" ); document.write( "--------------Subtraction eliminates px
\n" ); document.write( "5p - 5x = 0
\n" ); document.write( "divide equation by 5
\n" ); document.write( "p - x = 0
\n" ); document.write( "therefore p = x
\n" ); document.write( ":
\n" ); document.write( "replace p with x in the 1st simplified equation
\n" ); document.write( "x*x - 5x = 36
\n" ); document.write( "form a quadratic equation
\n" ); document.write( "x^2 - 5x - 36 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-9)(x+4) =
\n" ); document.write( "only the positive solution wanted her
\n" ); document.write( "x = 9 calenders were bought
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this, original price = $9
\n" ); document.write( "9(9 - 5) = 36\r
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