document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887719>Question 887719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The scrap value at the end of its useful life is given by S(n)=C(1-r)^n, Where C is the original cost, n is the useful life of the machine in years, and r is the constant annual percentage of value lost. Find the scrap value of the original machine. Original Cost: $52,000; Life: 11 years; annual rate of value lost:11% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536826 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The scrap value at the end of its useful life is given by S(n)=C(1-r)^n, Where C is the original cost, n is the useful life of the machine in years, and r is the constant annual percentage of value lost.<BR>\n" );
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document.write( "Find the scrap value of the original machine. Original Cost: $52,000; Life: 11 years; annual rate of value lost:11%<BR>\n" );
document.write( "S(11) = 52000*(1-0.11)^11 <BR>\n" );
document.write( "S(11) = 52000*0.89^11<BR>\n" );
document.write( "S(11) = 52000*0.2775<BR>\n" );
document.write( "S(11) = $14,430.90<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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