document.write( "Question 887699: Solve the following systems graphically\r
\n" ); document.write( "\n" ); document.write( "-x+3y=8\r
\n" ); document.write( "\n" ); document.write( "x+y=2
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Algebra.Com's Answer #536822 by algebrapro18(249)\"\" \"About 
You can put this solution on YOUR website!
To graph a line all you need is two points on that line. You can either pick points and plug them into the equations given or, and this is how I will do it, you can get both equations into slope intercept form which will give you the two points you need to graph each line.
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\n" ); document.write( "\n" ); document.write( "So first we need to solve each equation for y to get it into slope intercept form.
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\n" ); document.write( "\n" ); document.write( "-x+3y = 8 add x to both sides
\n" ); document.write( "3y = 8+x divide both sides by 3
\n" ); document.write( "y = 8/3 + 1/3x
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\n" ); document.write( "\n" ); document.write( "x+y=2 subtract x from both sides
\n" ); document.write( "y = 2-x
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\n" ); document.write( "\n" ); document.write( "Now that we have both equations in slope intercept form we can look at each equation individually. \"y=8%2F3%2B%281%2F3%29x\" tells us that the y intercept is 8/3 and the slope is 1/3. So we know that the graph goes through the point (0,8/3) from the y-intercept. And remembering that slope is the change in y over the change in x we know that the graph then goes up one and over 3. So our new point would be (0+3,8/3+1) or (3,11/3). You can plot these two points and then connect the points with the line.
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\n" ); document.write( "\n" ); document.write( "Next we look at \"y+=+2-x\". The y intercept is 2 and the slope is -1. So we know that the graph goes through the point (0,2) from the y-intercept. Moving down 1 and over 1 puts our next point at (0+1,2-1) or (1,1). Plotting these two points will yield your line.
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\n" ); document.write( "\n" ); document.write( "To finish this problem you will look to see where the two lines intersect. This will be your solution. I will leave this for you to do. \r
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