document.write( "Question 887725: Completely factor the expression.
\n" ); document.write( "x2+10x+16
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Algebra.Com's Answer #536821 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2%2B10x%2B16\", we can see that the first coefficient is \"1\", the second coefficient is \"10\", and the last term is \"16\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"16\" to get \"%281%29%2816%29=16\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"16\" (the previous product) and add to the second coefficient \"10\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"16\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"16\":\r
\n" ); document.write( "\n" ); document.write( "1,2,4,8,16\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-4,-8,-16\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"16\".\r
\n" ); document.write( "\n" ); document.write( "1*16 = 16
\n" ); document.write( "2*8 = 16
\n" ); document.write( "4*4 = 16
\n" ); document.write( "(-1)*(-16) = 16
\n" ); document.write( "(-2)*(-8) = 16
\n" ); document.write( "(-4)*(-4) = 16\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"10\":\r
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First NumberSecond NumberSum
1161+16=17
282+8=10
444+4=8
-1-16-1+(-16)=-17
-2-8-2+(-8)=-10
-4-4-4+(-4)=-8
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"2\" and \"8\" add to \"10\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"2\" and \"8\" both multiply to \"16\" and add to \"10\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"10x\" with \"2x%2B8x\". Remember, \"2\" and \"8\" add to \"10\". So this shows us that \"2x%2B8x=10x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%282x%2B8x%29%2B16\" Replace the second term \"10x\" with \"2x%2B8x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2x%29%2B%288x%2B16%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B2%29%2B%288x%2B16%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B2%29%2B8%28x%2B2%29\" Factor out \"8\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x%2B2%29\" Combine like terms. Or factor out the common term \"x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2%2B10x%2B16\" factors to \"%28x%2B8%29%28x%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E2%2B10x%2B16=%28x%2B8%29%28x%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28x%2B8%29%28x%2B2%29\" to get \"x%5E2%2B10x%2B16\" or by graphing the original expression and the answer (the two graphs should be identical).
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