document.write( "Question 887638: a 3-digit number is 99 more than itself reversed. the units digit exceeds the tens digit by 2 while the hundreds digit exceeds the unit digit by 1. what is the possible value of the original number? \n" ); document.write( "
Algebra.Com's Answer #536812 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! a 3-digit number is 99 more than itself reversed. \n" ); document.write( " \r\n" ); document.write( " 100h+10t+u = 100u+10t+h+99\r\n" ); document.write( "\r\n" ); document.write( "Simplify\r\n" ); document.write( "\r\n" ); document.write( " 99h-99u = 99\r\n" ); document.write( "\r\n" ); document.write( "Divide through by 99\r\n" ); document.write( "\r\n" ); document.write( " h-u = 1\r\n" ); document.write( " \n" ); document.write( "the units digit exceeds the tens digit by 2 \n" ); document.write( " \r\n" ); document.write( "u=t+2\r\n" ); document.write( " \n" ); document.write( "the hundreds digit exceeds the unit digit by 1 \n" ); document.write( " \r\n" ); document.write( "h=u+1\r\n" ); document.write( "\r\n" ); document.write( "So we have to solve this system:\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |