document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887688>Question 887688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the weight that can be safely supported by a 2 inch by 6 inch support beam varies inversely with its length. a builder finds that a support beam that is 8 feet long will support 900 pounds. find the weight that can be safely supported by a beam that is 18 feet long. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536800 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A variation problem.  p for pounds, x for length of beam.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28p=k%2Fx%29 ALIGN=MIDDLE  ALT=\"highlight_green%28p=k%2Fx%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  k is a constant.  \r<BR>\n" );
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document.write( "The next part of the description means x=8 and p=900.  Find k using these values.  Return to the inverse variation equation and use the value for k to find p when x=18. </SPAN>\n" );
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