document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887663>Question 887663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 15 men working 6 hours a day can do a piece of work in 20 days. how many men working 8  hours a day can do it in 25 days. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536781 by </B><A HREF=/tutors/aboutme.mpl?userid=sadike007><B>sadike007(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sadike007><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let us do a ratio and proportion technique. it takes 15 men 6 hours per day for 20 days to make one piece.. so it takes 120 hours for 15 men.\r<BR>\n" );
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document.write( "it takes x to make one piece in 8 hours for 25 days,\r<BR>\n" );
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document.write( "this is what we have now.\r<BR>\n" );
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document.write( "15 men &#8594; 1 piece/120 hours<BR>\n" );
document.write( "x men &#8594; 1 piece/ 200 hours.\r<BR>\n" );
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document.write( "we now 'cross multiply' and get\r<BR>\n" );
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document.write( "x(1/120)=15(1/200)<BR>\n" );
document.write( "x=9.. therefore it takes 9 men to work 8 hours per day for 25 days to make one piece </SPAN>\n" );
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