document.write( "Question 887628: A lawn sprinkler sprays water 8 feet at full pressure as it rotates 360 degrees. If the water pressure is reduced by 50%, what is the difference in the area covered?
\n" ); document.write( "The choices are:
\n" ); document.write( "1)78.5
\n" ); document.write( "2)50.2
\n" ); document.write( "3)201.0
\n" ); document.write( "4)150.8
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Algebra.Com's Answer #536766 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i believe your answer is 150.8\r
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\n" ); document.write( "\n" ); document.write( "at full pressure, it sprays 8 feet out so 8 is your radius and the area covered is 8^2 * pi = 64 * pi.\r
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\n" ); document.write( "\n" ); document.write( "at half pressure, it sprays 4 feet out so 4 is your radius and the area covered is 4^2 * pi = 16 * pi.\r
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\n" ); document.write( "\n" ); document.write( "the difference in the area covered is 64 * pi - 16 * pi = 48 * pi.\r
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\n" ); document.write( "\n" ); document.write( "48 * pi = 150.7964... which rounds to 150.8.\r
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