document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887606>Question 887606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wire in the form of a square of side 7.5cm is bent into a circle. Find the radius of the circle.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536753 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A wire in the form of a square of side 7.5cm is bent into a circle. Find the radius of the circle.  <BR>\n" );
document.write( "Solution<BR>\n" );
document.write( "perimeter of square = 4xside of square <BR>\n" );
document.write( "                    = 4x7.5 =30 cm<BR>\n" );
document.write( "as per given conditions perimeter of square will be equal to circumference of circle <BR>\n" );
document.write( "circumference of circle = 30 cm <BR>\n" );
document.write( "2 pie r=30<BR>\n" );
document.write( "r =30/2x pie <BR>\n" );
document.write( "r= 30x7/2x22<BR>\n" );
document.write( "r= 210/44 = 105/22 =4.7727 cm<BR>\n" );
document.write( "Answer 4.8 cm approx </SPAN>\n" );
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