document.write( "Question 887580: y=cos x ans.y'=-sin x
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document.write( "i needed exact how to solve this problem \n" );
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Algebra.Com's Answer #536752 by rothauserc(4718) You can put this solution on YOUR website! y = cosx \n" ); document.write( "use definition of derivative \n" ); document.write( "y' = d cos(x)/dx = limit as delta approaches 0 of ((cos(x+delta) - cosx) / delta) \n" ); document.write( "now use the definition of cos (a +b) \n" ); document.write( "y' = d cos(x)/dx = limit as delta approaches 0 of (cos(x)cos(delta)-sin(x)sin(delta)-cos(x) / delta) = limit as delta approaches 0 of [(cos(delta)-1/delta * cos(x)) - (sin(delta)/delta * sin(x)] \n" ); document.write( "now use limits for sin and cos \n" ); document.write( "y' = d cos(x)/dx = (0 * cos(x)) - (1 * sin(x) = -sin(x)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |