document.write( "Question 887582: Please help with this? so confused...
\n" ); document.write( "Mr. Tucker has some cows and chickens. If there are 60 heads and 200 legs, how many chickens does he have?
\n" ); document.write( "

Algebra.Com's Answer #536737 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Think of the ratios of each animal to the body parts.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "COWS: 4 legs per cow. 1 head per cow.\r
\n" ); document.write( "\n" ); document.write( "CHICKENS: 2 legs per chicken. 1 head per chicken.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The available heads and legs suggests you should account for heads and account for legs. Notice that the ratio of any animal to heads is 1 to 1, so for 60 heads, Mr. Tucker must have 60 animals, combined chickens and cows.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "p = how many chickens (as in \"poultry\").
\n" ); document.write( "b = how many cows (think, \"bovine\").\r
\n" ); document.write( "\n" ); document.write( "You know \"highlight%28p%2Bb=60%29\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now account for legs:
\n" ); document.write( "\"p%2A2%2Bb%2A4=200\"
\n" ); document.write( "\"2p%2B4b=200\"
\n" ); document.write( "\"highlight%28p%2B2b=100%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Two equations in two unknowns. Finish the solution.
\n" ); document.write( "
\n" );