document.write( "Question 887564: you inherit $70,000 and plan to invest the money in two stocks paying 4% and 10% annual interest, respectively. How much should be invested at each rate if the total interest earned for the year is to be $4000? \n" ); document.write( "
Algebra.Com's Answer #536728 by mananth(16946)\"\" \"About 
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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 10.00% per annum ------------ Amount invested = y
\n" ); document.write( " 70000
\n" ); document.write( "Interest----- 4000.00
\n" ); document.write( "
\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 10.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 70000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 10.00% y= 4000
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 10 y= 400000.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -280000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 6 y= 120000
\n" ); document.write( "divide by 6
\n" ); document.write( " y = 20000
\n" ); document.write( "Part I 4.00% $ 50000
\n" ); document.write( "Part II 10.00% $ 20000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "50000 --------- 4.00% ------- 2000.00
\n" ); document.write( "20000 ------------- 10.00% ------- 2000.00
\n" ); document.write( "Total -------------------- 4000.00
\n" ); document.write( "
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