document.write( "Question 887532: Solve for x:\r
\n" ); document.write( "\n" ); document.write( "2^(3x-1) = 4^(2x)\r
\n" ); document.write( "\n" ); document.write( "I used logarithms to start this problem but I'm having trouble simplifying the problem. Here is what I have been able to do so far.\r
\n" ); document.write( "\n" ); document.write( "log2^(3x-1) = log4^(2x)
\n" ); document.write( "(3x-1)log2 = (2x)log4
\n" ); document.write( "(3x-1)= (2x)log4/log2 \n" ); document.write( "
Algebra.Com's Answer #536717 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Solve for x:\r
\n" ); document.write( "\n" ); document.write( "2^(3x-1) = 4^(2x)\r
\n" ); document.write( "\n" ); document.write( "I used logarithms to start this problem but I'm having trouble simplifying the problem. Here is what I have been able to do so far.\r
\n" ); document.write( "\n" ); document.write( "log2^(3x-1) = log4^(2x)
\n" ); document.write( "(3x-1)log2 = (2x)log4
\n" ); document.write( "(3x-1)= (2x)log4/log2
\n" ); document.write( "

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document.write( "You could very well use logs, but it's so much easier to use exponents, and not nearly as confusing. Thus, we have:
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document.write( "\"2%5E%283x+-+1%29+=+4%5E%282x%29\"
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document.write( "\"2%5E%283x+-+1%29+=+%282%5E2%29%5E%282x%29\" ------ Converting right-side to similar base: base 2
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document.write( "\"2%5E%283x+-+1%29+=+2%5E%284x%29\"
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document.write( "3x - 1 = 4x ----- Bases are equal, and so are their exponents
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document.write( "3x - 4x = 1
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document.write( "- x = 1
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document.write( "\"x+=+1%2F+-+1\"
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document.write( "\"highlight_green%28highlight_green%28x+=+-+1%29%29\"
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document.write( "You can do the check!! \r
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document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
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document.write( "Further help is available, online or in-person, for a fee, obviously. \r
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