document.write( "Question 887532: Solve for x:\r
\n" ); document.write( "\n" ); document.write( "2^(3x-1) = 4^(2x)\r
\n" ); document.write( "\n" ); document.write( "I used logarithms to start this problem but I'm having trouble simplifying the problem. Here is what I have been able to do so far.\r
\n" ); document.write( "\n" ); document.write( "log2^(3x-1) = log4^(2x)
\n" ); document.write( "(3x-1)log2 = (2x)log4
\n" ); document.write( "(3x-1)= (2x)log4/log2
\n" ); document.write( "

Algebra.Com's Answer #536711 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Where you left off:
\n" ); document.write( "\"+3x+-+1+=+2x%2A%28+log%284%29+%2F+log%282%29+%29+\"
\n" ); document.write( "\"+3x+-+1+=+2x%2A%28+log%28+2%5E2+%29+%2F+log%282%29+%29+\"
\n" ); document.write( "\"+3x+-+1+=+2x%2A2%2A%28+log%282%29+%2F+log%282%29+%29+\"
\n" ); document.write( "\"+3x+-+1+=+2x%2A2%2A1+\"
\n" ); document.write( "\"+3x+-+1+=+4x+\"
\n" ); document.write( "\"+x+=+-1+\"
\n" ); document.write( "-------------
\n" ); document.write( "check:
\n" ); document.write( "\"+3x+-+1+=+2x%2A%28+log%284%29+%2F+log%282%29+%29+\"
\n" ); document.write( "\"+3%2A%28-1%29+-+1+=+2%2A%28-1%29%2A%28+log%284%29+%2F+log%282%29+%29+\"
\n" ); document.write( "\"+-3+-1+=+-2%2A%28+log%284%29+%2F+log%282%29+%29+\"
\n" ); document.write( "\"+%28+-4+%29+%2F+%28+-2+%29++=+%28+log%284%29+%2F+log%282%29+%29+\"
\n" ); document.write( "\"+2%2Alog%282%29++=+log%284%29+\"
\n" ); document.write( "\"+log%284%29+=+log%284%29+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );