document.write( "Question 887526: . Raisins make up two thirds of a well-mixed bowl of peanuts and raisins. If half the mixture is removed and replaced with just peanuts, what fraction of the bowl will be raisins? \n" ); document.write( "
Algebra.Com's Answer #536695 by 2897696(96)\"\" \"About 
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in the bowl there are:
\n" ); document.write( "2/3 raisins
\n" ); document.write( "1/3 peanuts (3/3 -2/3)\r
\n" ); document.write( "\n" ); document.write( "remove 1/2 of the 2/3 raisins:
\n" ); document.write( "2/3 -1/2
\n" ); document.write( "4/6 - 3/6
\n" ); document.write( "1/6 raisins left in the bowl\r
\n" ); document.write( "\n" ); document.write( "add 3/6 raisins with peanuts:
\n" ); document.write( "3/6 now peanuts + original peanuts=5/6 total amount of peanuts\r
\n" ); document.write( "\n" ); document.write( "ANSWER: 1/6 of the bowl is raisins
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