document.write( "Question 887420: Find the equation of the tangent line to y=3x^2+0.6x-3 at x=1.5 \n" ); document.write( "
Algebra.Com's Answer #536606 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Find the equation of the tangent line to y=3x^2+0.6x-3 at x=1.5 \n" ); document.write( ". \n" ); document.write( "y-value when x=1.5 \n" ); document.write( "y=3x^2+0.6x-3 \n" ); document.write( "y=3(1.5)^2+0.6(1.5)-3 \n" ); document.write( "y=6.75+0.9-3 \n" ); document.write( "y=4.65 \n" ); document.write( ". \n" ); document.write( "Now, you have a point at (1.5, 4.65) \n" ); document.write( ". \n" ); document.write( "Next find the first derivative: \n" ); document.write( "y' = 6x + 0.6 \n" ); document.write( "slope at x=1.5 is \n" ); document.write( "6(1.5) + 0.6 \n" ); document.write( "9.6 (slope) \n" ); document.write( ". \n" ); document.write( "Now, using the slope (9.6) and the single point (1.5, 4.65) plug into \"point-slope\" form: \n" ); document.write( "y - y1 = m(x - x1) \n" ); document.write( "y - 4.65 = 9.6(x - 1.5) \n" ); document.write( "y - 4.65 = 9.6x - 14.4 \n" ); document.write( "y = 9.6x - 9.75 (equation of line in \"slope-intercept\" form) \n" ); document.write( " \n" ); document.write( " |