document.write( "Question 887395: 1f x+y =6,y+z =7 and x+z=9, what is the average of x,y and z?
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Algebra.Com's Answer #536584 by jim_thompson5910(35256)\"\" \"About 
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Add the equations to get\r
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\n" ); document.write( "\n" ); document.write( "x+y =6
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\n" ); document.write( "2x+2y+2z=22\r
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\n" ); document.write( "\n" ); document.write( "Factor out 2 \r
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\n" ); document.write( "\n" ); document.write( "2x+2y+2z=22\r
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\n" ); document.write( "\n" ); document.write( "2(x+y+z)=22\r
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\n" ); document.write( "\n" ); document.write( "then divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "2(x+y+z)=22\r
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\n" ); document.write( "\n" ); document.write( "2(x+y+z)/2=22/2\r
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\n" ); document.write( "\n" ); document.write( "x+y+z = 11\r
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\n" ); document.write( "\n" ); document.write( "Now we divide the sum of x,y,z by 3 to average x,y,z\r
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\n" ); document.write( "\n" ); document.write( "(x+y+z)/3 = 11/3\r
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\n" ); document.write( "\n" ); document.write( "So the mean or average of x,y,z is 11/3
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