document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887386>Question 887386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A garden has the shape of a right triangle with one leg 7 meters longer than the other. The hypotenuse is 7 meters less than twice the length of the shorter leg. What is the length of the shorter leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536583 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A garden has the shape of a right triangle with one leg 7 meters longer than the other. The hypotenuse is 7 meters less than twice the length of the shorter leg. What is the length of the shorter leg?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=length of shorter leg<BR>\n" );
document.write( "x+7=length of longer leg<BR>\n" );
document.write( "2x-7=length of hypotenuse<BR>\n" );
document.write( "By the pythagorean theorem:<BR>\n" );
document.write( "x^2+(x+7)^2=(2x-7)^2<BR>\n" );
document.write( "x^2+x^2+14x+49=4x^2-28x+49<BR>\n" );
document.write( "2x^2-42x=0<BR>\n" );
document.write( "2x(x-21)=0<BR>\n" );
document.write( "x=0 (reject)<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=21<BR>\n" );
document.write( "x+7=28<BR>\n" );
document.write( "2x-7=35<BR>\n" );
document.write( "length of shorter leg=21 m<BR>\n" );
document.write( "length of longer leg=28 m<BR>\n" );
document.write( "length of hypotenuse=35 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );