document.write( "Question 887329: The lenght of a rectangle is 4 yards less than 5 times the width. If the perimeter is 184 yards find the lenght and the width of the reftangle \n" ); document.write( "

Algebra.Com's Answer #536530 by algebrapro18(249) $\"\"$ $\"About$

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Let the length of the rectangle be L and let the width be W. Now we know that the length of the rectangle is 4 yards less than 5 times the width. An equation to express this would be:
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\n" ); document.write( "\n" ); document.write( "L=5W-4
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\n" ); document.write( "\n" ); document.write( "We also know that the perimeter is 184 yards and that to find the perimeter of a rectangle is 2l + 2w. We know that:
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\n" ); document.write( "\n" ); document.write( "2L+2W = 184
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\n" ); document.write( "\n" ); document.write( "Since we know an equation for the length we can plug that into the second equation and solve for Width.
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\n" ); document.write( "\n" ); document.write( "2L+2W = 184 Plug in L=5W-4
\n" ); document.write( "2(5W-4)+2W = 184 Distribute
\n" ); document.write( "10W-8+2W = 184 Combine like terms
\n" ); document.write( "12W-8 = 184 Add 8 to both sides
\n" ); document.write( "12W = 192 Divide both sides by 12
\n" ); document.write( "W = 16
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\n" ); document.write( "\n" ); document.write( "So we know that the width of the rectangle is 16 yards. We can now plug back into our equation for length to find the length.
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\n" ); document.write( "\n" ); document.write( "L=5W-4
\n" ); document.write( "L=5(16)-4
\n" ); document.write( "L=76\r
\n" ); document.write( "\n" ); document.write( "So we found that the width is 16 yards and the length is 76 yards. \n" ); document.write( "

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