document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887196>Question 887196</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the function of the form y=loga^x  whose graph is given. I was given the point (1/2, -1) Thank you for your time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536477 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using point (1/2, -1), x = 0.5 and y = -1, therefore<BR>\n" );
document.write( "-1 = log base a (0.5)<BR>\n" );
document.write( "using definition of logarithms, we get<BR>\n" );
document.write( "0.5 = a^-1<BR>\n" );
document.write( "1/a = 0.5<BR>\n" );
document.write( "multiply both sides of = by a (note a is not = 0)<BR>\n" );
document.write( "0.5a = 1<BR>\n" );
document.write( "a = 1/0.5 = 2<BR>\n" );
document.write( "therefore the log equation is<BR>\n" );
document.write( "y = log base 2 (x)<BR>\n" );
document.write( "check answer<BR>\n" );
document.write( "-1 = log base 2 (0.5) = -1<BR>\n" );
document.write( "our answer checks<BR>\n" );
document.write( " </SPAN>\n" );
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