document.write( "Question 74674: What is the equation of a horizontal line that passes through the point at (-2,-3)?\r
\n" ); document.write( "\n" ); document.write( "I have been working on this problem and I still do not understand it. May some one please help me? Thank you
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Algebra.Com's Answer #53645 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
A horizontal line will have the slope of 0. This is because the y value does not change but the x value changes. For instance, in the slope formula
\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" a horizontal line will have identical y values while the x changes. For instance, if we pick a horizontal line that goes through (0,2) and (2,2) we get:
\n" ); document.write( "\"m=%282-2%29%2F%282-0%29=0%2F2=0\"
\n" ); document.write( "So any horizontal line will have a slope of zero. Now plug in m=0 and the point (-2,-3) into the point slope equation
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"
\n" ); document.write( "\"y-%28-3%29=0%28x-%28-2%29%29\"Plug in m=0 and (\"x%5B1%5D\",\"y%5B1%5D\")=(-2,-3)
\n" ); document.write( "\"y%2B3=0x%2B2%280%29\"Distribute the 0 to each term
\n" ); document.write( "\"y=0-3\"Subtract 3 from both sides
\n" ); document.write( "So the equation is
\n" ); document.write( "\"+y=-3\"
\n" ); document.write( "If we graphed the equation, we would get:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-3%29+\"Graph of \"y=-3\"(dark red line)
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