document.write( "Question 74668: we are doing these types of questions in class. i am having a problem understanding how to solve.can you help?\r
\n" ); document.write( "\n" ); document.write( "the foci of the ellipse x^2/a^2+y^2/b^2=1b>a are_______\r
\n" ); document.write( "\n" ); document.write( "thanks for any insight into this..
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Algebra.Com's Answer #53641 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%5E2+%2F+a%5E2%29+%2B+%28y%5E2+%2F+b%5E2%29+=+1\" (b > a)
\n" ); document.write( "My math book shows this general equation in a slightly different
\n" ); document.write( "form, but I'm not confused by it. My book says
\n" ); document.write( "\"%28y%5E2%2Fa%5E2%29+%2B+%28x%5E2%2Fb%5E2%29=+1\" (a > b)
\n" ); document.write( "It says that this equation is centered at the origin and the major axis
\n" ); document.write( "is the y-axis. It really says exactly the same thing as your
\n" ); document.write( "equation, with a and b reversed. Just say \"The denominator associated
\n" ); document.write( "with the y^2 term is greater than the denominator associated with the
\n" ); document.write( "x^2 term.\"
\n" ); document.write( "I'm told \"c%5E2+=+a%5E2+-+b%5E2\" and the foci are at \"y+=+%2Bc\" and \"y+=+-c\"
\n" ); document.write( "\"y+=+%2Bsqrt%28a%5E2+-+b%5E2%29\" the 1st foci
\n" ); document.write( "\"y+=+-sqrt%28a%5E2+-+b%5E2%29\" the 2nd foci
\n" ); document.write( "If b > a in your equation, the foci would be on the x-axis
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