document.write( "Question 887133: The area of a rectangle is 52 and the length is 5 less than twice the width. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #536402 by Alan3354(69443) You can put this solution on YOUR website! Step 1, try the factors of 52 in pairs. \n" ); document.write( "---- \n" ); document.write( "1*52 NG \n" ); document.write( "2*26 NG \n" ); document.write( "etc \n" ); document.write( "============== \n" ); document.write( "If that doesn't work: \n" ); document.write( "L*W = 52 \n" ); document.write( "L = 2W - 5 \n" ); document.write( "Sub for L in the 1st eqn \n" ); document.write( "(2W - 5)*W = 52 \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "======================= \n" ); document.write( "W = 6.5 \n" ); document.write( "L = 8 \n" ); document.write( " |