document.write( "Question 887065: A leaves Mumbai at 6am and reaches Bangalore at 10am. B leaves Bangalore at 8am and reaches Mumbai at 11:30am. At what time do they cross each other ? \n" ); document.write( "
Algebra.Com's Answer #536383 by rothauserc(4718)\"\" \"About 
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The distance between Mumbai and Bangalore is 987 Km
\n" ); document.write( "We use rate times time = distance
\n" ); document.write( "let Ra be the rate of A
\n" ); document.write( "let Rb be the rate of B
\n" ); document.write( "Time for A to cover the 987 Km is 4 hours
\n" ); document.write( "Time for B to cover he 987 Km is 3.5 hours
\n" ); document.write( "therefore we have two equations
\n" ); document.write( "Ra * 4 = 987
\n" ); document.write( "Ra = 987 / 4 = 246.75 Km per hour
\n" ); document.write( "Rb * 3.5 = 987
\n" ); document.write( "Rb = 987 / 3.5 = 282 Km per hour
\n" ); document.write( "note that A has been travelling for two hours before B gets started, therefore we must subtract 2*246.75 from 987
\n" ); document.write( "987 - 2*246.75 = 493.5
\n" ); document.write( "now A and B cross when together they have covered 493.3 Km, therefore we have
\n" ); document.write( "note that t = time we are interested in
\n" ); document.write( "246.75t + 282t = 493.5
\n" ); document.write( "528.75t = 493.5
\n" ); document.write( "t = 493.5 / 528.75
\n" ); document.write( "t = 0.933333333 hour
\n" ); document.write( "convert t to minutes
\n" ); document.write( "t = 0.933333333 * 60 = 56 minutes
\n" ); document.write( "we will now add 56 minutes to B's start time of 8am
\n" ); document.write( "therefore the time A and B cross is 8:56 am\r
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