document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887104>Question 887104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first cyclist leaves point A and averages 10km/h . 30 minutes later a second cyclist leaves point A and averages 15 km/hour . How many minutes till he catches up to the first cyclist ? And how many km did it take to catch up ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536366 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> After 30 minutes, A = 5, B = 0<BR>\n" );
document.write( "After 1 hour, A = 10, B = 7.5 (half of 15kmh since he left 30 mins later)<BR>\n" );
document.write( "After 90 minutes, A = 15, B = 15<BR>\n" );
document.write( "B catches up with A 90 minutes after A leaves (60 minutes after B leaves) at the distance of 15km. </SPAN>\n" );
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