document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=887077>Question 887077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance traveled by a ball rolling down a ramp is given by s(t)=2.25t^2, where t is the time in seconds after the ball is released, and s(t) is measured in feet.  Evaluate the average velocity of the ball for the time interval [1.0,1.1].\r<BR>\n" );
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document.write( "Please show me your work in this problem,  Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536336 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using given formula calculate the distance covered at t=1.0 and t=1.1, then subtract s(1.0) from s(1.1)<BR>\n" );
document.write( "s(1.1) = 2.25*(1.1)^2 = 2.7225<BR>\n" );
document.write( "s(1.0) = 2.25*(1.0)^2 = 2.25<BR>\n" );
document.write( "s(1.1) - s(1.0) = 0.4725<BR>\n" );
document.write( "average velocity(Va) equals (delta distance) / (delta time)<BR>\n" );
document.write( "Va = 0.4725 / 0.1 = 4.725<BR>\n" );
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