document.write( "Question 887044: Express 8j^23 - 8(j^3)^2 in rectangular form. \n" ); document.write( "
Algebra.Com's Answer #536328 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We will use \r\n" );
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document.write( "1. \"j%5E2=-1\", \r\n" );
document.write( "2. \"%28-1%29%5EEVEN=1\", \r\n" );
document.write( "3. \"%28-1%29%5EODD=-1\", \r\n" );
document.write( "4. \"j%5EODD=J%5EEVEN%2Aj\", \r\n" );
document.write( "5. \"j%5EEVEN=%28j%5E2%29%5EN\"\r\n" );
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document.write( "\"8j%5E23+-+8%28j%5E3%29%5E2\"\r\n" );
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document.write( "          We multiply exponents\r\n" );
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document.write( "\"8j%5E23+-+8j%5E6\"\r\n" );
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document.write( "          We factor out 8\r\n" );
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document.write( "\"8%28j%5E23-j%5E6%29\"\r\n" );
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document.write( "          Break odd power of j into even power times j:\r\n" );
document.write( "          Write even power as power of jē:\r\n" );
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document.write( "\"8%28j%5E22%2Aj-%28j%5E2%29%5E3%29\"\r\n" );
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document.write( "          Write even power as power of jē\r\n" );
document.write( "          Substitute -1 for jē:\r\n" );
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document.write( "\"8%28%28j%5E2%29%5E11%2Aj-%28-1%29%5E3%29\"\r\n" );
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document.write( "          Substitute -1 for jē:\r\n" );
document.write( "          Use \"%28-1%29%5EODD=-1\"\r\n" );
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document.write( "\"8%28%28-1%29%5E11%2Aj-%28-1%29%29\"\r\n" );
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document.write( "          Use \"%28-1%29%5EODD=-1\"\r\n" );
document.write( "          Write -(-1) as +1\r\n" );
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document.write( "\"8%28%28-1%29%2Aj%2B1%29\"\r\n" );
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document.write( "          Write (-1)*j as -j\r\n" );
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document.write( "\"8%28-j%2B1%29\"\r\n" );
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document.write( "          Distribute 8\r\n" );
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document.write( "\"-8j%2B8\"\r\n" );
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document.write( "          Write j-term second:\r\n" );
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document.write( "\"8-8j\"\r\n" );
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document.write( "Edwin
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