document.write( "Question 887049: The probability of getting the product a perfect square (square of a
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document.write( "natural number), when two dice are thrown together, is:
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Algebra.Com's Answer #536325 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! The perfect squares are: 1, 4, 9, 16, ...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can't get 1 since 2 is the smallest sum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can't get 16 since 12 is the largest sum.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are two perfect squares we could get: 4, 9\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are really 3 ways to roll a 4 and they are\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4 = 1+3 \n" ); document.write( "4 = 2+2 \n" ); document.write( "4 = 3+1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 4 ways to roll a 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9 = 3+6 \n" ); document.write( "9 = 4+5 \n" ); document.write( "9 = 5+4 \n" ); document.write( "9 = 6+3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So there are 3+4 = 7 ways to roll either a 4 or a 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is out of 6*6 = 36 ways possible. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Final Answer: 7/36 \n" ); document.write( " \n" ); document.write( " |