document.write( "Question 887023: Please help me! \r
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document.write( "Starting at home, Jessica travelled uphill to the hardware store for 75 minutes at just 4 mph. She then travelled back home along the same path downhill at a speed of 12 mph.\r
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document.write( "What is her average speed for the entire trip from home to the hardware store and back?
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Algebra.Com's Answer #536321 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Same distance d both ways. \n" ); document.write( "RT=D rate time distance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "_______________rate________time_________distance \n" ); document.write( "UP_____________4___________ \n" ); document.write( "DOWN__________12___________t______________d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify the UP time hours and compute d:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "_______________rate________time____________distance \n" ); document.write( "UP_____________4___________ \n" ); document.write( "DOWN__________12___________t_________________d=5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The time going DOWN can now easily be computed as \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Total distance is BOTH WAYS, up and down \n" ); document.write( "Total time in hours is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Average Speed, \n" ); document.write( " \n" ); document.write( " |