document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886743>Question 886743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B are running on a track having 8 laps to the mile.<BR>\n" );
document.write( "If they run in opposite directions they meet every 20 seconds.<BR>\n" );
document.write( "If they run in the same direction it requires 3 minutes for A to overtake B.<BR>\n" );
document.write( "Find the rate of each in per second.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536285 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A and B are running on a track having 8 laps to the mile.<BR>\n" );
document.write( "If they run in opposite directions they meet every 20 seconds.<BR>\n" );
document.write( "If they run in the same direction it requires 3 minutes for A to overtake B.<BR>\n" );
document.write( "Find the rate of each in per second.<BR>\n" );
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document.write( "Find the no. of ft per lap: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5280%2F8 ALIGN=MIDDLE  ALT=\"5280%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 660 ft<BR>\n" );
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document.write( "Let a = A's speed in ft/sec<BR>\n" );
document.write( "Let b = B's speed<BR>\n" );
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document.write( "3 min = 180 sec<BR>\n" );
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document.write( "When running in opposite directions, their relative speed is the sum<BR>\n" );
document.write( "When running in the same direction, their relative speed is the difference<BR>\n" );
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document.write( "Write a distance equation for each way; dist = time * relative speed<BR>\n" );
document.write( "20(a + b) = 660<BR>\n" );
document.write( "and<BR>\n" );
document.write( "180(a - b) = 660<BR>\n" );
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document.write( "multiply the 1st equation by 9<BR>\n" );
document.write( "180(a + b) = 5940<BR>\n" );
document.write( "180(a - b) = 660<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "180a + 180b = 5940<BR>\n" );
document.write( "180a - 180b = 660<BR>\n" );
document.write( "-------------------adding eliminates b, find a<BR>\n" );
document.write( "360a = 6600<BR>\n" );
document.write( "a = 6600/360<BR>\n" );
document.write( "a = 18<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > ft/sec is A's running speed<BR>\n" );
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document.write( "Find b using the 1st original equation<BR>\n" );
document.write( "20(18.333 + b ) = 660<BR>\n" );
document.write( "simplify, divide both sides by 20<BR>\n" );
document.write( "18.333 + b = 33<BR>\n" );
document.write( "b = 33 - 18.333<BR>\n" );
document.write( "b = 14<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > ft/sec is B's speed<BR>\n" );
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document.write( "Confirm that in the 2nd equation<BR>\n" );
document.write( "180(18.333 - 14.667) = 660<BR>\n" );
document.write( "180(3.667) = 660<BR>\n" );
document.write( "659.998 ~ 660<BR>\n" );
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