document.write( "Question 886943: How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid? \n" ); document.write( "
Algebra.Com's Answer #536253 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid? \n" ); document.write( "*** \n" ); document.write( "let x=amt of 60% solution to mix \n" ); document.write( "50+x=amt of final mixture \n" ); document.write( ".. \n" ); document.write( "60%x+24%*50=50%(50+x) \n" ); document.write( ".60x+12=25+.50x \n" ); document.write( ".10x=13 \n" ); document.write( "x=130 \n" ); document.write( "amt of 60% solution to mix=130 gal \n" ); document.write( " |