document.write( "Question 886951: If Lisa and Mark can mow their lawn together in 1 hour, and Lisa can mow the lawn by herself in 3 hours, what is Mark's rate, working alone? I came up with this equation: t1/3 + t =1 and of course my answer is wrong. \r
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Algebra.Com's Answer #536246 by MathTherapy(10810)\"\" \"About 
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If Lisa and Mark can mow their lawn together in 1 hour, and Lisa can mow the lawn by herself in 3 hours, what is Mark's rate, working alone? I came up with this equation: t1/3 + t =1 and of course my answer is wrong.
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\n" ); document.write( "Let time Mark takes to mow by himself, be M
\n" ); document.write( "Then Mark can mow 1/M of lawn in 1 hour
\n" ); document.write( "Lisa can mow lawn in 3 hours, or 1/3 of lawn in 1 hour
\n" ); document.write( "Therefore, \"1%2FM+%2B+1%2F3+=+1%2F1\"
\n" ); document.write( "\"1%2FM+%2B+1%2F3+=+1\"
\n" ); document.write( "3 + M = 3M ------ Multiplying by LCD, 3M
\n" ); document.write( "3 = 3M - M
\n" ); document.write( "2M = 3
\n" ); document.write( "M, or time Mark takes, alone, to mow = \"3%2F2\", or \"1%261%2F2\" hours
\n" ); document.write( "Mark's rate: \"1%2FM\", or \"1%2F%283%2F2%29\", or \"highlight_green%28highlight_green%282%2F3%29%29\" of lawn in 1 hour \n" ); document.write( "
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