document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886844>Question 886844</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 2.5 hours an airplane travels 1150 km against the wind. It takes 50 mins to travel 450 km with the wind. find the speed of the wind and the speed of the airplane in still air. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536205 by </B><A HREF=/tutors/aboutme.mpl?userid=verclau><B>verclau(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=verclau><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=verclau><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So you note the speed of airplane with Va and the speed of wind with Vw and you have the formula v=distance/time=d/t and from the problem you have Va-Vw=1150km/2.5h=460km/h and Va+Vw=450km/(5/6)h=540km/h and now you have 2 equations which you add them and obtain 2Va-Vw+Vw=1000km/h => Va=500km/h the speed of airplane and Vw=540-Va=40km/h the speed of wind.Done. </SPAN>\n" );
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