document.write( "Question 74622: Lane invested $22,000, part at 8% and part at 7%. If the total interest at the end of the year is $1,710, how much did she invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #53620 by checkley75(3666)\"\" \"About 
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.08X+.07(22,000-X)=1,710
\n" ); document.write( ".08X+1,540-.07X=1,710
\n" ); document.write( ".01X=1,710-1,540
\n" ); document.write( ".01X=170
\n" ); document.write( "X=170/.01
\n" ); document.write( "X=17,000 AMOUNT INVESTED @ 8%.
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