document.write( "Question 74622: Lane invested $22,000, part at 8% and part at 7%. If the total interest at the end of the year is $1,710, how much did she invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #53620 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .08X+.07(22,000-X)=1,710 \n" ); document.write( ".08X+1,540-.07X=1,710 \n" ); document.write( ".01X=1,710-1,540 \n" ); document.write( ".01X=170 \n" ); document.write( "X=170/.01 \n" ); document.write( "X=17,000 AMOUNT INVESTED @ 8%. \n" ); document.write( " |