document.write( "Question 74646: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number. \n" ); document.write( "
Algebra.Com's Answer #53611 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! X+12=Y, X=Y-12 \n" ); document.write( "X+2Y=39 NOW SUBSTITUTE (Y-12) FOR X IN THIS EQUATION & SOLVE FOR X \n" ); document.write( "(Y-12)+2Y+39 \n" ); document.write( "Y-12+2Y=39 \n" ); document.write( "3Y=39+12 \n" ); document.write( "3Y=51 \n" ); document.write( "Y=51/3 \n" ); document.write( "Y=17 ANSWER FOR THE LARGER NUMBER. \n" ); document.write( "X+12=17 \n" ); document.write( "X=17-12 \n" ); document.write( "X=5 ANSWER FOR THE SMALLER NUMBER. \n" ); document.write( "PROOF \n" ); document.write( "5+2*17=39 \n" ); document.write( "5+34 \n" ); document.write( "39=39 \n" ); document.write( " |