document.write( "Question 74646: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number. \n" ); document.write( "
Algebra.Com's Answer #53611 by checkley75(3666)\"\" \"About 
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X+12=Y, X=Y-12
\n" ); document.write( "X+2Y=39 NOW SUBSTITUTE (Y-12) FOR X IN THIS EQUATION & SOLVE FOR X
\n" ); document.write( "(Y-12)+2Y+39
\n" ); document.write( "Y-12+2Y=39
\n" ); document.write( "3Y=39+12
\n" ); document.write( "3Y=51
\n" ); document.write( "Y=51/3
\n" ); document.write( "Y=17 ANSWER FOR THE LARGER NUMBER.
\n" ); document.write( "X+12=17
\n" ); document.write( "X=17-12
\n" ); document.write( "X=5 ANSWER FOR THE SMALLER NUMBER.
\n" ); document.write( "PROOF
\n" ); document.write( "5+2*17=39
\n" ); document.write( "5+34
\n" ); document.write( "39=39
\n" ); document.write( "
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