document.write( "Question 886707: Please help me solve this problem: Find g(a+1) when g(x)=2x+1. \n" ); document.write( "
Algebra.Com's Answer #536065 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To find \"g%28a%2B1%29\", we just plug in \"x+=+a%2B1\". That means you replace EVERY copy of x with 'a+1' and simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29=2x%2B1\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29=2%28x%29%2B1\" This step is optional, but it helps to have every 'x' on the right side in parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"g%28a%2B1%29=2%28a%2B1%29%2B1\" Everywhere you see an \"x\", replace it with \"a%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%28a%2B1%29=2a%2B2%2A1%2B1\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"g%28a%2B1%29=2a%2B2%2B1\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"g%28a%2B1%29=2a%2B3\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "And we're done. The final answer is \"g%28a%2B1%29=2a%2B3\"
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