document.write( "Question 886649: The difference of two numbers is 6. The sum of 2 times the larger number and 3 times the smaller number is 37. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #536059 by JulietG(1812)\"\" \"About 
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A - B = 6, which also means that A = B + 6
\n" ); document.write( "2A + 3B = 37
\n" ); document.write( "Take the value of A from the first equation and plug it in to the second.
\n" ); document.write( "2A + 3B = 37
\n" ); document.write( "2(B+6) + 3B = 37
\n" ); document.write( "Distribute
\n" ); document.write( "2B + 12 + 3B = 37
\n" ); document.write( "Add
\n" ); document.write( "5B + 12 = 37
\n" ); document.write( "Subtract 12 from each side
\n" ); document.write( "5B = 25
\n" ); document.write( "Divide each side by 5
\n" ); document.write( "B = 5
\n" ); document.write( ".
\n" ); document.write( "If B is 5 and the difference between A and B is 6, then A = 11
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\n" ); document.write( "2A + 3B = 37
\n" ); document.write( "(2*11) + (3*5) = 37
\n" ); document.write( "22 + 15 = 37
\n" ); document.write( "37 = 37
\n" ); document.write( "Success!
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