document.write( "Question 886649: The difference of two numbers is 6. The sum of 2 times the larger number and 3 times the smaller number is 37. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #536059 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! A - B = 6, which also means that A = B + 6 \n" ); document.write( "2A + 3B = 37 \n" ); document.write( "Take the value of A from the first equation and plug it in to the second. \n" ); document.write( "2A + 3B = 37 \n" ); document.write( "2(B+6) + 3B = 37 \n" ); document.write( "Distribute \n" ); document.write( "2B + 12 + 3B = 37 \n" ); document.write( "Add \n" ); document.write( "5B + 12 = 37 \n" ); document.write( "Subtract 12 from each side \n" ); document.write( "5B = 25 \n" ); document.write( "Divide each side by 5 \n" ); document.write( "B = 5 \n" ); document.write( ". \n" ); document.write( "If B is 5 and the difference between A and B is 6, then A = 11 \n" ); document.write( ". \n" ); document.write( "2A + 3B = 37 \n" ); document.write( "(2*11) + (3*5) = 37 \n" ); document.write( "22 + 15 = 37 \n" ); document.write( "37 = 37 \n" ); document.write( "Success! \n" ); document.write( " |