document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886676>Question 886676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gabriela is 42 years old and Omar is 3 years old.\r<BR>\n" );
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document.write( "How many years will it take until Gabriela is only 4 times as old as Omar? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #536033 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=536033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gabriela is 42 years old and Omar is 3 years old. <BR>\n" );
document.write( "How many years will it take until Gabriela is only 4 times as old as Omar?<BR>\n" );
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document.write( "Let the number of years be \"x\"::<BR>\n" );
document.write( "Equation::<BR>\n" );
document.write( "42+x = 4(3+x)<BR>\n" );
document.write( "42+x = 12 + 4x<BR>\n" );
document.write( "3x = 30<BR>\n" );
document.write( "x = 10 <BR>\n" );
document.write( "In 10 years Gabriela will be 52 and Omar will be 13<BR>\n" );
document.write( "4*13 = 52<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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