document.write( "Question 886566: A train travels at a certain average speed for a distance of 63 km. Thereafter it travels a distance of 72 km with an average speed of 6 km/hr more than the original speed. Total time taken to complete the journey is 3 hours. What is the original average speed of the train ? \n" ); document.write( "
Algebra.Com's Answer #535986 by josgarithmetic(39617)\"\" \"About 
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r = original speed for first 63 km.\r
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\n" ); document.write( "\n" ); document.write( "________________rate_________time_______distance
\n" ); document.write( "First___________r____________(___)______63
\n" ); document.write( "Last____________r+6_________(___)_______72
\n" ); document.write( "TOTAL_________________________3\r
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\n" ); document.write( "\n" ); document.write( "Basic Rule in Uniform Rates Travel, RT=D.
\n" ); document.write( "Use to find T=D/R.\r
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\n" ); document.write( "\n" ); document.write( "________________rate_________time_______distance
\n" ); document.write( "First___________r____________\"63%2Fr\"_______63
\n" ); document.write( "Last____________r+6_________\"72%2F%28r%2B6%29\"_______72
\n" ); document.write( "TOTAL_________________________3\r
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\n" ); document.write( "\n" ); document.write( "Solve this equation for r:
\n" ); document.write( "\"highlight_green%2863%2Fr%2B72%2F%28r%2B6%29=3%29\"
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