document.write( "Question 886566: A train travels at a certain average speed for a distance of 63 km. Thereafter it travels a distance of 72 km with an average speed of 6 km/hr more than the original speed. Total time taken to complete the journey is 3 hours. What is the original average speed of the train ? \n" ); document.write( "
Algebra.Com's Answer #535986 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! r = original speed for first 63 km.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "________________rate_________time_______distance \n" ); document.write( "First___________r____________(___)______63 \n" ); document.write( "Last____________r+6_________(___)_______72 \n" ); document.write( "TOTAL_________________________3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Basic Rule in Uniform Rates Travel, RT=D. \n" ); document.write( "Use to find T=D/R.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "________________rate_________time_______distance \n" ); document.write( "First___________r____________ \n" ); document.write( "Last____________r+6_________ \n" ); document.write( "TOTAL_________________________3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve this equation for r: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |