document.write( "Question 886487: 2 yd ³ of soil containing 35% sand was mixed into 6yd ³ of soil containing 15% sand. What is the sand content of the mixture? \n" ); document.write( "
Algebra.Com's Answer #535928 by lwsshak3(11628)\"\" \"About 
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2 yd ³ of soil containing 35% sand was mixed into 6yd ³ of soil containing 15% sand. What is the sand content of the mixture?
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\n" ); document.write( "35%*2+15%*6=x%*8
\n" ); document.write( ".70+.90=8x
\n" ); document.write( "x=1.6/8=.20
\n" ); document.write( "sand content of the mixture=20% \n" ); document.write( "
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