document.write( "Question 886482: A novice hiker can walk a 50 mile trail in 10 hr. the hiker traveled the first 20 miles of the trail at a constant rate before decreasing the rate by 1 mph. Find the rate for each part of the hike. \r
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document.write( "I know the average of the whole thing would be 5 mph.\r
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document.write( "I tried 5.5mph for the first 20 and 4.5 for the last 30 but the time I got is 10 hours 17 min. \n" );
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Algebra.Com's Answer #535927 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A novice hiker can walk a 50 mile trail in 10 hr. the hiker traveled the first 20 miles of the trail at a constant rate before decreasing the rate by 1 mph. Find the rate for each part of the hike. \n" ); document.write( "*** \n" ); document.write( "let x=rate 1st 20 mi \n" ); document.write( "x-1=rate remaining 30 mi \n" ); document.write( "travel time=distance/rate \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( "lcd: x(x-1) \n" ); document.write( "20(x-1)+30x=10(x^2-x) \n" ); document.write( "20x-20+30x=10x^2-10x \n" ); document.write( "10x^2-60x+20=0 \n" ); document.write( "x^2-6x+2=0 \n" ); document.write( "solve by quadratic formula: \n" ); document.write( " \n" ); document.write( "a=1, b=-6, c=2 \n" ); document.write( "ans: \n" ); document.write( "x≈0.35 (reject, not reasonable) \n" ); document.write( "or \n" ); document.write( "x≈5.65 \n" ); document.write( ".. \n" ); document.write( "rate 1st 20 mi≈5.65 mph \n" ); document.write( "rate remaining 30 mi≈4.65 mph \n" ); document.write( " \n" ); document.write( " |